Multiplication of two-digit numbers
In Vedic Maths, Multiplication of two digit numbers can be done by Nikhilam Sutra (Base Method)
Case 1: - Both Numbers are higher than Base (10)
For Example:- 13 x 16
Step 1 –
| Number | Base | Difference |
|---|---|---|
| 13 (X1) | 10 (Y) | + 3 (Z1) |
| 16 (X2) | 10 (Y) | + 6 (Z2) |
Y= nearest power of 10 i.e. 10, 100, 1000, 10000.
Thus nearest power of 10 to the number 13 and 16 is 10.
Z 1 = X 1 – Y, Z 2 = X 2 - Y
Step 2 -
| Part A | Part B |
|---|---|
| 13 + 6 | 3 x 6 |
| 19 | 18 |
Part A = (X1 + Z 2)
Part B = Z1 x Z2
Step 3 -
| Part A | Part B |
|---|---|
| 19 + 1 | 8 |
| 20 | 8 |
Ans :- 208
Rule 1:- No. of zeros in base is equal to no. of digits in part B.
Therefore 1 carried over to Part A
Now Club Part A with Part B for Final Answer
Another Example of Two Digit Numbers higher than Base (10)
17 x 18
Step 1 –
| Number | Base | Difference |
|---|---|---|
| 17 (X1) | 10 (Y) | + 7 (Z1) |
| 18 (X2) | 10 (Y) | + 8 (Z2) |
Y= nearest power of 10 i.e 10, 100, 1000, 10000.
Thus nearest power of 10 to the number 17 and 18 is 10.
Z 1 = X 1 – Y , Z 2 = X 2 - Y
Step 2: -
| Part A | Part B |
|---|---|
| 17 + 8 | 7 x 8 |
| 25 | 56 |
Part A = (X1 + Z2)
Part B = (Z1 x Z2)
Step 3 :-
| Part A | Part B |
|---|---|
| 25 +5 | 6 |
| 30 | 6 |
Ans :- 306
Rule 1:- No. of zeros in base is equal to no. of digits in part B.
Therefore 5 carried over to Part A
Now Club Part A with Part B for Final Answer.